Question

Solve 1st and 2nd equations alone​

Answer 1

Answer:

a) First equation of motion:

Let an object moves from A to D in time interval t.

Acceleration of moving object = V2- V1 / t2 - t1

If initial velocity is u and final velocity is v then

=> a = v - u / t - 0

=> at = v - u

=> v = u + at

Hence Proved

b) Second equation of motion:

Distance travelled by object = area under graph

= area of rec. ACBO + area of triangle ADC

= (OA) × (OB) + 1/2 × (AC) × (CD)

= ut + 1/2 × (OB) × (BD - BC)

= ut + 1/2 × t × (v-u)

= ut + 1/2 × t × (at)

s = ut + 1/2 at2  

Hence Proved.

c) Third equation of motion:

Distance travelled by object = area under graph

S = 1/2 (Sum of Parallel sides) x tS = 1/2 × (u+v) x t

2S / u+v = t … (1)

From the first equation of motion we can also write

v - u / a = t … (2)

Equating equations (1) and (2)

2S / u + v = v - u /a

=> 2as = (v-u) × (v+u) = v2

- u

2

=> v2

= u

2

+2as

Hence Proved.

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Explanation: