Question

Solve 1st and 3rd Question plz

Answer 1

Answer:

Step-by-step explanation:

in the first one instead of x just put the value of 3 u will  get the value of k

sorry i dont know the 3rd one....hope it helps pls chat getting bored

Answer 2

>>> 1 <<<

${x}^{2} - 2kx - 6 = 0$
If x = 3 is one root of the above quadratic equation that substituting x = 3 must satisfy the above equation.

${3}^{2} - 2k(3) - 6 = 0$
$- 2k(3) = 6 - 9$
$6k = 3$
$k = \frac{1}{2}$

>>> 3 <<<

This type of questions are solved by Pythagorean theorem,

answer is
$\sqrt{ {x}^{2} + {y}^{2} }$