solve 1st question of this excersise solve any for advance
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Hii,your answer is here
cosec A=5/4
Taken from the pic,
PR^2=PQ^2+QR^2
=>QR=√{(5)^2-(4)^2}
=√9=3
So,CotA=QR/PQ=3/4
SinA=4/5[Opposite of Cosec]
CosA=QR/PR=3/5
~~~~Thanks ~~~~
cosec A=5/4
Taken from the pic,
PR^2=PQ^2+QR^2
=>QR=√{(5)^2-(4)^2}
=√9=3
So,CotA=QR/PQ=3/4
SinA=4/5[Opposite of Cosec]
CosA=QR/PR=3/5
~~~~Thanks ~~~~
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