Question

solve [(2^-1 + 4^-1) ÷ 2]^2

Answer 1

Hey friend,
Here is the answer you were looking for:
[(2^-1+4^-1) ÷ 2]^2

= [(1/2 + 1/4) × 1/2]^2

= [( 1×2+1/4) × 1/2]^2

= (3/4 × 1/2)^2

= (3/8)^2

= (9/64)


Hope this helps!!!

@Mahak24

Thanks...
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Answer 2

Hello

$( {2}^{ - 1} + {4}^{ - 1} \div {2)}^{2}$

$( \frac{1}{2} + \frac{1}{4} \div {2)}^{2}$

$( \frac{2 + 1}{4} \div {2)}^{2}$

$( \frac{ 3}{4} \div {2)}^{2}$

$( \frac{3}{4} \times { \frac{1}{2} })^{2}$

$\frac{ {3}^{2} }{ {8}^{2} }$

$\frac{9}{64}$
Answer .

Kul !!
Regards - Me