Math, asked by matekarrashmi, 11 hours ago

Solve 2^2×-5(2^×+1)+16=0.​

Answers

Answered by prarthanagohil312
0

Answer:

2²×(-5)(2+1)+16=0

-20(3)+16=0

by solving

0=0

LHS=RHS

Step-by-step explanation:

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