solve 2^(2x)+2^(x+2)-4×2^3=0
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Answered by
46
Step-by-step explanation:
(2^x)^2 + (2^x )(2^2) - 32 = 0
let y = 2^x, replace the value in above eq.
y^2 + 4y - 32 = 0
y^2 - 4y + 8y -32 = 0
y ( y - 4 ) + 8(y -4 ) = 0
(y - 4)(y + 8) =0
hence
y = 4 or -8
but -8 value leads to imaginary number, hence considering only value 4.
y = 4
replace y with 2^x
2^x = 4
2^x. = 2^2
x = 2
Answered by
24
Answer:
x=2
Step-by-step explanation:
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