Question

solve 2^(2x)+2^(x+2)-4×2^3=0

Answer 1

Step-by-step explanation:

(2^x)^2 + (2^x )(2^2) - 32 = 0

let y = 2^x, replace the value in above eq.

y^2 + 4y - 32 = 0

y^2 - 4y + 8y -32 = 0

y ( y - 4 ) + 8(y -4 ) = 0

(y - 4)(y + 8) =0

hence

y = 4 or -8

but -8 value leads to imaginary number, hence considering only value 4.

y = 4

replace y with 2^x

2^x = 4

2^x. = 2^2

x = 2

Answer 2

Answer:

x=2

Step-by-step explanation:

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