Question

solve 2^3(5^0+3^2x)=224/27

Answer 1

Answer:

Step-by-step explanation:

8*(1+3^(2x))=224/27 multiply by 27

8*27(1+3^(2x))=224

216+216*3^(2x)=224

216*3^(2x)=224-216

216*3^(2x)=8

3^(2x)=8/216

3^(2x)=1/27 now write 1/27 as 1/3^3 and finally as 3^-3

3^(2x)=3^-3 now compare the exponents

2x=-3

x= -3/2

Answer 2

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