Question

solve = 2/3x +1/3= 5/3x+ 7/3​

Answer 1

Answer:

X= -1/2

Step-by-step explanation:

$\frac{2}{3x} + \frac{1}{3} = \frac{5}{3x} + \frac{7}{3} \\ \\ \frac{2}{3x} - \frac{5}{3x} = \frac{7}{3} - \frac{1}{3} \\ \\ \frac{2 - 5}{3x} = \frac{7 - 1}{3} \\ \\ \frac{ - 3}{3x} = \frac{6}{3} \\ \frac{ - 3}{3x} = 2 \\ - 3 = 6x \\ x = \frac{ - 3}{6} \\ x = \frac{ - 1}{2}$

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Answer 2

Answer:

$\green{\frac{2}{3x}+\frac{1}{3}=\frac{5}{3x}+\frac{7}{3}\quad :\quad x=-\frac{1}{2}\quad \left(\mathrm{Decimal}:\quad x=-0.5\right)}$

Step-by-step explanation:

$\frac{2}{3x}+\frac{1}{3}=\frac{5}{3x}+\frac{7}{3}$

$\black{\mathrm{Find\:Least\:Common\:Multiplier\:of\:}3x,\:3:\quad 3x}$

$\gray{\mathrm{Multiply\:by\:LCM=}3x}$

$\frac{2}{3x}\cdot \:3x+\frac{1}{3}\cdot \:3x=\frac{5}{3x}\cdot \:3x+\frac{7}{3}\cdot \:3x$

$\gray{\mathrm{Simplify}}$

$\frac{2}{3x}\cdot \:3x+\frac{1}{3}\cdot \:3x=\frac{5}{3x}\cdot \:3x+\frac{7}{3}\cdot \:3x$

$\gray{\mathrm{Simplify\:}\frac{2}{3x}\cdot \:3x:\quad 2}$

$\gray{\mathrm{Simplify\:}\frac{1}{3}\cdot \:3x:\quad x}$

$\gray{\mathrm{Simplify\:}\frac{5}{3x}\cdot \:3x:\quad 5}$

$\gray{\mathrm{Simplify\:}\frac{7}{3}\cdot \:3x:\quad 7x}$

$2+x=5+7x$

$\gray{\mathrm{Subtract\:}2\mathrm{\:from\:both\:sides}$

$2+x-2=5+7x-2$

$\gray{\mathrm{Simplify}}$

$x=7x+3$

$\gray{\mathrm{Subtract\:}7x\mathrm{\:from\:both\:sides}}$

$x-7x=7x+3-7x$

$\gray{\mathrm{Simplify}}$

$-6x=3$

$\gray{\mathrm{Divide\:both\:sides\:by\:}-6}$

$\frac{-6x}{-6}=\frac{3}{-6}$

$\gray{\mathrm{Simplify}}$

$x=-\frac{1}{2}$