solve 2^5x-1 = 4×2^3x+1
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Given 2^5x-1 = 4*2^3x+1
then 2^5x-1 = 2^3x+3 (as 4 = 2^2)
As base is same so does the exponents
then 5x-1 = 3x+3 => 2x = 4 => x = 2.
then 2^5x-1 = 2^3x+3 (as 4 = 2^2)
As base is same so does the exponents
then 5x-1 = 3x+3 => 2x = 4 => x = 2.
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