solve
(2+6yz) * (x^2 y^2 +2yz)
using property
pls help me....i will definitely mark the person brainliest if he or she is the first answerer
Answers
Answered by
2
Answer:
Step-by-step explanation:
(2+6 y z) * (x^2 y^2 +2 y z)
= 2 * (x^2 y^2 +2 y z) + 6 y z * (x^2 y^2 +2 y z)
= 2 x^2 y^2 + 4 y z + 6 x^3 y^3 + 12 x^2 y^2
= 14 x^2 y^2 + 4 y z + 6 x^3 y^3
janhavi728:
where did the z in your answer go in the 3rd step
and it should also not be 12x^2 in the third step there should only be x and y
sorry, i left the z . so the solution from the 3rd step
2 x^2 y^2 + 4 y z + 6 x^2 y^3 z + 12 y^2 z^2
so the given above is the solution for that sum.
Answered by
2
first we multiply each number of the second bracket with 2 then, multiply the second bracket with 6yz and add both the answers -
(2+6yz) × (x²y²+2yz)
= (2x²2y²+4yz) + (6x²yz 6y³z + 12y²z²)
Now, we open the brackets and add the like terms
= 2x²2y² + 4yz + 6x²yz 6y³z + 12y²z²
There are no like terms so we keep it like this and the expression is solved!
Hope it helps! have a nice day!
Please mark brainliest:)
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