Solve 2 cos^2 x + 3 sin x = 0
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sinx= -2cos square x/3
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Solution for x is,
\begin{eqalign}
&$x=2\pi n_{2}-i\ln(\sqrt{3}-\sqrt{2})\text{, }n_{2}\in \mathrm{Z}$\\
&$x=\pi n_{3}-i\ln(\sqrt{2}+\sqrt{3})\text{, }n_{3}\in \mathrm{Z}$\\
&$x=2\pi n_{1}-i\ln(\sqrt{2}-\sqrt{3})\text{, }n_{1}\in \mathrm{Z}$
\end{eqalign}
\begin{eqalign}
&$x=2\pi n_{2}-i\ln(\sqrt{3}-\sqrt{2})\text{, }n_{2}\in \mathrm{Z}$\\
&$x=\pi n_{3}-i\ln(\sqrt{2}+\sqrt{3})\text{, }n_{3}\in \mathrm{Z}$\\
&$x=2\pi n_{1}-i\ln(\sqrt{2}-\sqrt{3})\text{, }n_{1}\in \mathrm{Z}$
\end{eqalign}
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