solve [2 (i),(ii)] 3 (i),(ii)
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2 (1ans 3/8) 2(2ans 1/2) 3(1ans 1-2√3 ) 3(2ans1/3)
rishiraj02102002:
no not right
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2 i) 4/3sin²60 + cos²60 - sin²45
= (4/3)(3/4) + 1/4 - 1/2
= 1 + 1/4 - 1/2
= 3/4
ii) -(3/4)(1/3) + 5(4/3) + (1/4)(1/3) - 2(3/4)
= -1/4 + 20/3 + 1/12 - 3/2
= 81/12 - 7/4
= 27/4 - 7/4
= 20/4
= 5
3 i) (2)(√3/2) - (3)(2)
= √3 - 6
ii) (2/3)(1/2) +2(0) -4(1/4) - (3/2)(4/3) +3
= 1/3 + 0 - 1 - 2 + 3
= 1/3
hope it helps you
@di
= (4/3)(3/4) + 1/4 - 1/2
= 1 + 1/4 - 1/2
= 3/4
ii) -(3/4)(1/3) + 5(4/3) + (1/4)(1/3) - 2(3/4)
= -1/4 + 20/3 + 1/12 - 3/2
= 81/12 - 7/4
= 27/4 - 7/4
= 20/4
= 5
3 i) (2)(√3/2) - (3)(2)
= √3 - 6
ii) (2/3)(1/2) +2(0) -4(1/4) - (3/2)(4/3) +3
= 1/3 + 0 - 1 - 2 + 3
= 1/3
hope it helps you
@di
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