solve : 2 sin 2θ = √3
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Given,
2sin2theata = root 3
sin 2 theata = (root 3)/2
sin 2 theata = sin 60
2 theata = 60
theata = 60/2
therefore , theata = 30
2sin2theata = root 3
sin 2 theata = (root 3)/2
sin 2 theata = sin 60
2 theata = 60
theata = 60/2
therefore , theata = 30
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