Solve 2 sin θ = sin θ ( 0° ≤ θ ≤ 360° )
Answers
Answered by
1
Answer:
The solutions are
S
=
{
30
º
,
150
º
,
270
º
}
Explanation:
The equation is
2
sin
2
θ
+
sin
θ
−
1
=
0
We can factorise the LHS
(
2
sin
θ
−
1
)
(
sin
θ
+
1
)
=
0
Therefore,
sin
θ
=
−
1
,
⇒
,
θ
=
270
º
sin
θ
=
1
2
,
⇒
,
θ
=
30
º
,
150
º
I HOPE IT WOULD HELP YOU AND MAKE ME BRAINIEST...
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