Question

Solve 2 upon x + 2 upon 3y = 1 upon 6 and 3 upon x + 2 upon y=0

Answer 1

3/x+2/y=0

take lcm or multiply both lhs and rhs with xy

3y+2x=0

3y=-2x

substitute 3y=-2x in the other equation

2/x+2/(-2x)=1/6

2/x-1/x=1/6

as they are like fractions we can perform subtraction

1/x-=1/6

therefore x=6

and substituting x=6 in any eqn find the value of y