Question

solve. 2(x-1) -3(4x+1) = 2(x-1) -3(5x-4) +6x​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

2(x-1) - 3(4x+1) = 2(x-1) - 3(5x - 4) + 6x​

→ $\red{\sf{ [ 2(x) - 2(1) ] }}$ - 3(4x+1) = 2(x-1) - 3(5x - 4) + 6x​

→ $\red{ \sf (2x - 2) }$ - 3(4x+1) = 2(x-1) - 3(5x - 4) + 6x​

→ (2x - 2) - $\red{\sf[ 3(4x)+3(1)] }$ = 2(x-1) - 3(5x - 4) + 6x

→ (2x - 2) - $\red{\sf (12x+3) }$ = 2(x-1) - 3(5x - 4) + 6x

→ (2x - 2) $\red{\sf -12x-3 }$ = 2(x-1) - 3(5x - 4) + 6x

→ 2x - 2 - 12x - 3 = $\pink{\sf [2(x) - 2(1)] }$ - 3(5x - 4) + 6x

→  2x - 2 - 12x - 3 = $\pink{\sf (2x - 2) }$ - 3(5x - 4) + 6x

→  2x - 2 - 12x - 3 = (2x - 2) - $\pink{\sf [3(5x) - 3(4) ]}$ + 6x

→  2x - 2 - 12x - 3 = (2x - 2) - $\pink{\sf (15x - 12) ]}$ + 6x

→  2x - 2 - 12x - 3 = (2x - 2) - 15x + 12 + 6x

→ (2x - 12x) - 3 - 2 = 2x + 6x - 15x - 2  + 12

→ (- 10x) - 5 = 8x - 15x + 10

→ (-10x) - 5 = -7x + 10

→ (-10x) + 7x = 10 + 5  

[ ∵ taking (-5) to RHS and (-7x) to LHS ]

→ (-3x) = 15

→ x = 15 ÷ (-3)

→ x = -5