Question

solve 2^x+1=4^x-3 find the solution​

Answer 1

$\Huge{\bold{\mathrm{\underline{\red{QUESTION}}}}}$

${2}^{x + 1} = {4}^{x - 3}$

$\Huge{\bold{\mathrm{\underline{\red{ANSWER}}}}}$

${2}^{x + 1} = {2}^{2(x - 3)}$

$= > {2}^{x + 1} = { 2}^{2x - 6}$

$= > x + 1 = 2x - 6$

$= > 2x - x = 6 + 1$

$x = 7$

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Answer 2

$2^{x} + 1 = 4^{x} - 3$

$1 + 3 = 4^{x} - 2^{x}$

$4 = 2^{x}$

$\frac{4}{2} = x$

$2 = x$

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