Question

solve 2/x+2/3y=1/6;3/x+2/y=0 using elimination methodplzz slove this soon

Answer 1

$\frac{2}{x} + \frac{2}{3y} = \frac{1}{6} .....(i)$
$\frac{3}{x} + \frac{2}{y} = 0.....(ii)$
$\frac{2}{y} = - \frac{3}{x}$
Substitute in (i)

$\frac{2}{x} + \frac{1}{3} (\frac{ - 3}{x} ) = \frac{1}{6}$
$\frac{1}{x} = \frac{1}{6}$
$x = 6$
Put x=6 in (ii)

$\frac{3}{6} + \frac{2}{y} = 0.....(ii)$
$y = ( - 4)$