Solve 2^x-2 = (square root 2)^x
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Before we take the square of both sides, we need to isolate the radical term.
\begin{aligned}\sqrt{2x-7}-3&=4\\ \\ \sqrt{2x-7}&=7\\ \\ \end{aligned}
2x−7
−3
2x−7
=4
=7
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