Math, asked by patkarsonali155, 3 months ago

solve 2(x-3)=3/5(x+4)​

Answers

Answered by srishtishaw53
1

2

(

3

)

=

3

5

(

+

4

)

2(x-3)=\frac{3}{5}(x+4)

2(x−3)=53(x+4)

Solve

1

Distribute

2

(

3

)

=

3

5

(

+

4

)

{\color{#c92786}{2(x-3)}}=\frac{3}{5}(x+4)

2(x−3)=53(x+4)

2

6

=

3

5

(

+

4

)

{\color{#c92786}{2x-6}}=\frac{3}{5}(x+4)

2x−6=53(x+4)

2

Combine multiplied terms into a single fraction

2

6

=

3

5

(

+

4

)

2x-6=\frac{3}{5}(x+4)

2x−6=53(x+4)

2

6

=

3

(

+

4

)

5

2x-6=\frac{3(x+4)}{5}

2x−6=53(x+4)

3

Distribute

2

6

=

3

(

+

4

)

5

2x-6=\frac{{\color{#c92786}{3(x+4)}}}{5}

2x−6=53(x+4)

2

6

=

3

+

1

2

5

2x-6=\frac{{\color{#c92786}{3x+12}}}{5}

2x−6=53x+12

4

Add

6

6

6

to both sides of the equation

2

6

=

3

+

1

2

5

2x-6=\frac{3x+12}{5}

2x−6=53x+12

2

6

+

6

=

3

+

1

2

5

+

6

2x-6+{\color{#c92786}{6}}=\frac{3x+12}{5}+{\color{#c92786}{6}}

2x−6+6=53x+12+6

5

Simplify

Add the numbers

2

=

3

+

1

2

5

+

6

2x=\frac{3x+12}{5}+6

2x=53x+12+6

6

Multiply all terms by the same value to eliminate fraction denominators

2

=

3

+

1

2

5

+

6

2x=\frac{3x+12}{5}+6

2x=53x+12+6

5

2

=

5

(

3

+

1

2

5

+

6

)

5 \cdot 2x=5(\frac{3x+12}{5}+6)

5⋅2x=5(53x+12+6)

7

Cancel multiplied terms that are in the denominator

5

2

=

5

(

3

+

1

2

5

)

+

5

6

5 \cdot 2x=5(\frac{3x+12}{5})+5 \cdot 6

5⋅2x=5(53x+12)+5⋅6

5

2

=

3

+

1

2

+

5

6

5 \cdot 2x=3x+12+5 \cdot 6

5⋅2x=3x+12+5⋅6

8

Multiply the numbers

5

2

=

3

+

1

2

+

5

6

{\color{#c92786}{5}} \cdot {\color{#c92786}{2}}x=3x+12+5 \cdot 6

5⋅2x=3x+12+5⋅6

1

0

=

3

+

1

2

+

5

6

{\color{#c92786}{10}}x=3x+12+5 \cdot 6

10x=3x+12+5⋅6

9

Multiply the numbers

1

0

=

3

+

1

2

+

5

6

10x=3x+12+{\color{#c92786}{5}} \cdot {\color{#c92786}{6}}

10x=3x+12+5⋅6

1

0

=

3

+

1

2

+

3

0

10x=3x+12+{\color{#c92786}{30}}

10x=3x+12+30

10

Add the numbers

1

0

=

3

+

1

2

+

3

0

10x=3x+{\color{#c92786}{12}}+{\color{#c92786}{30}}

10x=3x+12+30

1

0

=

3

+

4

2

10x=3x+{\color{#c92786}{42}}

10x=3x+42

11

Subtract

3

3x

3x

from both sides of the equation

1

0

=

3

+

4

2

10x=3x+42

10x=3x+42

1

0

3

=

3

+

4

2

3

10x{\color{#c92786}{-3x}}=3x+42{\color{#c92786}{-3x}}

10x−3x=3x+42−3x

12

Simplify

Combine like terms

Combine like terms

7

=

4

2

7x=42

7x=42

13

Divide both sides of the equation by the same term

7

=

4

2

7x=42

7x=42

7

7

=

4

2

7

\frac{7x}{{\color{#c92786}{7}}}=\frac{42}{{\color{#c92786}{7}}}

77x=742

14

Simplify

Cancel terms that are in both the numerator and denominator

Divide the numbers

=

6

x=6

x=6

Show less

Solution

=

6

please fllw me

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