Question

solve 2^(x-3) find the x​

Answer 1

$</p><p> {2}^{x - 3} = \frac{ {2}^{x} }{ {2}^{3} } = \frac{ {2}^{x} }{8} \\ \\ if \: {2}^{x - 3} = 1 \\ \frac{ {2}^{x} }{ {2}^{3} } = 1 \\ x = 3$

please mark me brainliest.