Math, asked by varshinichitikeshi, 4 days ago

Solve (2-x)+3 log 5 ^ 2 =log 5 (3^ x -5^ 2-x )

Answers

Answered by jlaymra

0

Answer:

logz+log5=2log3

Let us solve for x,

logx=2log3−log5

=log3

2

−log5

=log9−log5

=log(9/5)

∴x=9/5

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