Question

solve 2/x+3/y=2 and4/x+ 3/y=3​

Answer 1

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To solve :

( i ) $\bf{{\frac{2}{x}}+{\frac{3}{y}}=2}$

( ii ) $\bf{{\frac{4}{x}}+{\frac{3}{y}}=3}$

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$\bf (i) \frac{2}{x} + \frac{3}{y} = 2 \\ \\ \bf \frac{2}{x} + 3 = 2y \\ \\ \bf \frac{2 + 3x}{x} = 2y \\ \\ \bf 2 + 3x = 2xy \\ \bf \underline{ \underline{3x - 2xy = ( - 2)}}$

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$\bf (ii) \frac{4}{x} + \frac{3}{y} = 3 \\ \\ \bf \frac{4}{x} + 3 = 3y \\ \\ \bf \frac{4 + 3x}{x} = 3y \\ \\ \bf 4 + 3x = 3xy \\ \bf \underline{ \underline{3x - 3xy = ( - 4)}}$

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