Solve
2 – x/4≤1 + x/3; 3 – x < 4(x – 3), when (i) x is an integer (ii) x is a real
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The given inequality is 3x+8>2
⇒3x+8−8>2−8
⇒3x>−6
⇒
3
3x
>
3
−6
⇒x>−2
(i) The integers greater than −2 are −1,0,1,2,.......
Thus when x is an integer, the solutions of the given inequality are −1,0,1,2............
(ii) When x is a real number, the solutions of the given inequality are all the real numbers, which are greater than −2.
Thus in this case, the solution set is (−2,∞)
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