Question

solve 2(x-5)+3(x-2)=8+7(x-4) using only by the systematic method

Answer 1

The solution is

2x-10+3x-6=8+7x-28

5x-10-6=7x-20

5x-7x=-20+10+6

-2x=-4

x=2

Answer 2

2(x-5)+3(x-2)=8+7(x-4)
2x-10+3x-6=8+7x-28
5x-16=7x-20
5x-7x=-20+16
-2x=-4
2x=4
x=4/2
x=2