Solve :- (2-x) < (2/x+1)
YagamiLight:
what is the operation?
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Answered by
0
2-x<2/x+1
(3-x)<x+3/x+1
(x-3)(x+1)/x+3>0
x=(-3,-1) union (3, infinity)
(3-x)<x+3/x+1
(x-3)(x+1)/x+3>0
x=(-3,-1) union (3, infinity)
put values brother than check ur answer is wrong
thats (2/x )+1
o then I was erong
hmm edit it brother
Answered by
2
hey miss
here is ur answer
▶️⏩⏩⏩⏩⏩⏩⏩
(2-x) < (2/x+1)
0<(2+x/x) -(2-x)
0<(2+x-2x+x^2)/X
0<(x^2-x+2)/X
D is -ve of (x^2-2x+2)
so answer is X belongs to(0,oo)
▶️▶️▶️▶️▶️▶️▶️▶️
I hope it helps
#Prem^_^
here is ur answer
▶️⏩⏩⏩⏩⏩⏩⏩
(2-x) < (2/x+1)
0<(2+x/x) -(2-x)
0<(2+x-2x+x^2)/X
0<(x^2-x+2)/X
D is -ve of (x^2-2x+2)
so answer is X belongs to(0,oo)
▶️▶️▶️▶️▶️▶️▶️▶️
I hope it helps
#Prem^_^
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