Question

solve 2 X square + root 6x minus 6 is equals to zero by factorization method​

Answer 1

Answer:

take factors as root 6 and 2root 6, see the image

Answer 2

Answer:

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Step-by-step explanation:

Here....

$2 {x}^{2} + \sqrt{6}x \: - 6 = 0$

Since , we know that Here to get the product if the coefficient of x² and constant term...is 2x²(6) = 12x²

So to get the product 12x² and the sum √6x we will split the middle term...

$2 {x}^{2} + 2 \sqrt{6}x - \sqrt{6}x - 6 = 0$

$2x(x + \sqrt{6}) - \sqrt{6}(x + \sqrt{6}) = 0$

$(2x - \sqrt{6})(x + \sqrt{6}) = 0$

If.....

$2x - \sqrt{6} = 0 \\ therefore... \\ x = \frac{ \sqrt{6} }{2}$

If....

$x + \sqrt{6} = 0 \\ therefore... \\ x = - \sqrt{6}$

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