Question

solve: 2(x2+1/x2)-3(x-1/x)-1=0

Answer 1

2(x2+1/x2)-3(x-1/x)-1=0

x4+1/x-3x+3/x-1=0

x+4/x-1=0

x^2-x+4=0

x=-(-1)±{√(-1)^2-4×1×4}/2×1

x=1±√(-15)/2

Answer 2

The required value of x is $-\frac{1}{2},1$

Step-by-step explanation:

$2(\frac{x^{2}+1 }{x^{2} } )-3(\frac{x-1}{x})-1=0\\\\\Rightarrow \frac{2x^{2}+2 }{x^{2} } -(\frac{3x-3}{x})-1=0 \\\\\Rightarrow \frac{2x^{2}+2-x(3x-3)-x^{2} }{x^{2} } =0\\\\\Rightarrow\frac{2x^{2}+2-3x^{2} +3x-x^{2} }{x^{2} } =0\\\\\Rightarrow 2x^{2}+2-3x^{2} +3x-x^{2}=0$

Bring the like terms together

$\Rightarrow 2x^{2}-3x^{2} -x^{2} +3x+2=0\\\\\Rightarrow -2x^{2} +3x+2=0$

Using factorization method

$\Rightarrow -2x^{2} +4x-x+2=0\\\\\Rightarrow -2x(x-2)-1(x-2)=0\\\\\Rightarrow (-2x-1)(x-1)=0\\\\\Rightarrow -2x-1=0\\\\\Rightarrow -2x=1\\\\\Rightarrow x=-\frac{1}{2} \\\\or\\\\\Rightarrow x-1=0\\\\\Rightarrow x=1$

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2 upon X + 2 upon 3 Y is equal to 1 upon 6 3 upon X + 2 upon Y is equal to zero​

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