Math, asked by kaushikgaming112233, 6 months ago

Solve plzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz​

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Answers

Answered by sammyakjamdade
1

40 coins of 10p

30 coins of 50p

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Answered by angrejg93
0

Solve= let the no. of 70 coins be x and no. of 50p coins by y.

= x+y= 70[eq1]

or

x = 70-y

= 10x +50y = 1900. [eq2

time of no of 10 coins +y time the no of 50 p coins is equal to 1900p

=10(70-y) + 50y = 1900

= 700-10y +50y =1900

= 40y = 1200

=y = 30 coins of 50p

When yu replace the values in any of eq1 or eq2 (I will do it in eq1)

X+30 = 70

= X= 40 coins of 10 p

Step-by-step explanation:

To times 10p is 400 i.e. 4rs and 30Rs time 50p coins is 1500 i.e. 15rs.The sum gives yu 1900 or R's 19

Given : 70 coins of value of 10p and 50p in all total value of the money in, is R's 19or 1900

(100p^19)

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