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40 coins of 10p
30 coins of 50p
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Solve= let the no. of 70 coins be x and no. of 50p coins by y.
= x+y= 70[eq1]
or
x = 70-y
= 10x +50y = 1900. [eq2
time of no of 10 coins +y time the no of 50 p coins is equal to 1900p
=10(70-y) + 50y = 1900
= 700-10y +50y =1900
= 40y = 1200
=y = 30 coins of 50p
When yu replace the values in any of eq1 or eq2 (I will do it in eq1)
X+30 = 70
= X= 40 coins of 10 p
Step-by-step explanation:
To times 10p is 400 i.e. 4rs and 30Rs time 50p coins is 1500 i.e. 15rs.The sum gives yu 1900 or R's 19
Given : 70 coins of value of 10p and 50p in all total value of the money in, is R's 19or 1900
(100p^19)
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