Solve:
217x+131y=913
131x+217y=827
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From Ist equation we get,
x=(913-131y)/217
Substituting x in 2nd equation we get,131{913-131y)/217} + 217y =827
(119603-17161y)/217 +217 y =827
Taking LCM,
119603-17161y+47089y = 827*217
119603+29928y = 179459
29928y=179459-119603
29928y = 59856
y=59856/29928
y=2
Putting y=2 in 1st equation,we get
217x +262=913
217x = 913-262
217x = 651
x = 651/217
x = 3
Therefore, x=3 and y=2
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