solve 22/x+y+15/x-y=5and 55/x+y+45/x-y=14
Answers
Answer:
(x+y)²=7.4 and (x+y)²=7.14
Answer:
The solution for 22/x+y+15/x-y=5and 55/x+y+45/x-y=14 is:
y = 3 and x = 8
Explanation:
Let:
x + y = m and x - y = n
Doing the substitution we have:
22/m + 15/n = 5......................i)
55/m + 45/n = 14....................ii)
rewriting the equations we have:
22n + 15m = 5mn..................iii)
55n + 45m = 14mn..............iv)
Let's eliminate m by multiplying iii by 3 and subtracting the two equations.
11n = mn
Divide all through by n to get m:
m = 11
Substitute m in iii to get:
22n + 165 = 55n
55n - 22n = 165
33n = 165
n = 5
Since we have the values of m and n, we have that:
x + y = 11.........................v)
x - y = 5........................vi)
Let's eliminate y by adding the two equations:
2x = 16
x = 16/2 = 8
8 + y = 11
y = 11 - 8
y = 3