Math, asked by krishnendhukm2006, 2 days ago

Solve 24x<100, when
I) X is a natural number
ii) X is an integer​

Answers

Answered by rsrigangaram2
0

Answer:24100

Step-by-step ex        

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Answered by Anonymous
7

Let's first solve for the inequation given, then we will be solving for the given conditions

{:\implies \quad \sf 24x&lt;100}

Divide both sides by 24

{:\implies \quad \sf \dfrac{24x}{24}&lt;\dfrac{100}{24}}

{:\implies \quad \sf x&lt;\dfrac{25}{3}}

Now, as we need to take only natural numbers and integers, so we are not allowed to take rational numbers, also (25/3) ≈ 4.1666..., so we can just replace (25/3) by 4

{:\implies \quad \sf x&lt;4}

Now, for natural numbers, the solution set will be {\bf{\{1,2,3\}}} and for integers the solution set will be infinte,so here the solution set is {\bf{\{x\:|\:x\:is\:an\:integer,x&lt;4\}}}

Note:- Here, | symbol means "such that"

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