Solve √(25-x^2)=x-1 by factorization method
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square both sides of the equation
25 - x^2 = (x-1)^2
25 -x^2 = x^2 -2x+1
0 = 2x^2 -2x +1-25
2x^2 -2x -24 =0
x^2 -x -12 =0 [ dividing each term with 2]
x^2 -4x +3x -12=0
x(x-4)+3(x-4)=0
(x-4)(x+3)=0
therefore
x-4 =0 or x+3 =0
x= 4 or x= -3
25 - x^2 = (x-1)^2
25 -x^2 = x^2 -2x+1
0 = 2x^2 -2x +1-25
2x^2 -2x -24 =0
x^2 -x -12 =0 [ dividing each term with 2]
x^2 -4x +3x -12=0
x(x-4)+3(x-4)=0
(x-4)(x+3)=0
therefore
x-4 =0 or x+3 =0
x= 4 or x= -3
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