Question

solve 256x^2-32x+1=0 using quadratic formula

Answer 1

256x^2 - 32x + 1 = 0
=> 256x^2 - (16+16)x + 1 = 0
=> 256x^2-16x-16x+1=0
=> 16x(16x-1)-1(16x-1) = 0
=> (16x-1) (16x-1) = 0

Answer 2

Answer is (x= 1/16 ), (x=1/16 )

Hope it helps !!