solve ¡¡!!!!!!¡¡!¡!¡
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Answered by
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HEY FRND...
REFER TO THE ATTACHMENT...
# GUDIYA...
HOPE IT HELPS...!!! ☺☺
REFER TO THE ATTACHMENT...
# GUDIYA...
HOPE IT HELPS...!!! ☺☺
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Answered by
1
d=b²-4ac
=(-8k)²-4×8k×1
0=64k²-32k
32k=64k²
k=1/2
=(-8k)²-4×8k×1
0=64k²-32k
32k=64k²
k=1/2
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