Question

solve...................

Answer 1

This is the answer thank you dear          Mark me as brilliant

Answer 2

Answer:

199/3

Step-by-step explanation:

Let the digit on tens place be x

Let the digit on one's place be y

Number = 10x+y

We are given that the sum of the digits of two digit number together with 7 is three times the digit in tens place

$\Rightarrow x+y+7=3x$

$\Rightarrow y+7=2x$

$\Rightarrow y=2x-7$ ---1

Now we are given that If 8 is subtracted form the number so, the digits of the number interchange their position.

$\Rightarrow 10x+y-8=10y+x$

$\Rightarrow 9x-8=9y$

Substitute the value of y from 1

$\Rightarrow 9x-8=9(2x-7)$

$\Rightarrow 9x-8=18x-63$

$\Rightarrow 55=9x$

$\Rightarrow \frac{55}{9}=x$

So, Substitute the value in 1

$\Rightarrow y=2(\frac{55}{9})-7$

$\Rightarrow y=\frac{47}{9}$

Number = 10x+y= $10( \frac{55}{9})+\frac{47}{9}=\frac{199}{3}$

Hence the number is 199/3