Math, asked by myselfsingh28, 1 year ago

solve 27/x+y - 15/x-y= -2
and
30/x+y - 1/x-y = 3

Answers

Answered by Anonymous
54
hello here is your answer by Sujeet yaduvanshi ,


Let to be 1/x+y=@
Let to be 1/x-y=b

then,

27a-15b=-2 *30

30a-b=3*27

by elimination method for solving this question by elimination...

810a-450b=-60
810a-27b=81

______________

423b=141
b=141/432
b=1/3

Again

putting the value of y in another equation

27a-15b=-2
27a-15*1/3=-2
27a-5=-2
27a=-2+5
27a=3
a=3/27
a=1/9


Now,


1/x+y=1/9
x+y=9


1/x-y=1/3
x-y=3


then,


x+y=9
x-y=3
_____
2y=6
y=6/2
y=3

Again and again,

x+y=9
x+3=9
x=9-3
x=6


thanks
Answered by ayushmvm9
1

Answer:  y = 6, and x = 3

Insert  "x" and "y" value in both the equations, you will get

Eq - 1 as ( - 2 ) = ( - 2 ) and Eq - 2 as ( 3 ) = ( 3 )

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