Question

Solve 28
Plz do this fast as possible

Answer 1

(a)The three pairs are:

1.BD=CD.

2.AB=AC.

3.AD=AD(Common).

(b)Yes,∆ADB is congruent to ∆ADC.Bcoz,

BD=CD

AB=AC

AD=AD(Common)

By SSS congruency,

∆ADB is congruent to ∆ADC.

(c)Perpendicular from vertex of an isosceles ∆ bisects the base.
So,BD=DC

Answer 2

AD is perpendicular to BC so BD=CD
In triangle ADB andADC
AB=AC (given) AD=AD(common)
so by S.S.S triangle ADB is congruent to triangle ADC

BD=CD as AD dividesBC into two equal halves and is perpendicular to BC