Question

solve...................

Answer 1

hope this may help you

Answer 2

[tex]2sin^{2}x + sin^{2}2x=2 2sin^{2}x + (2sinxcosx)^{2} = 2 2sin^{2}x + 4sin^{2}x(1-sin^{2}x)=2 sin^{2}x + 2sin^{2}x - 2sin^{4}x =1 2sin^{4}x -2sin^{2}x - sin^{2}x + 1 = 0 2sin^{2}x(sin^{2}x-1)-1(sin^{2}x-1) = 0 (sin^{2}x- \frac{1}{2})(sin^{2}-1) =0 sin^{2}x = \frac{1}{2} sin^{2}x = 1 [/tex]

Now I don't think you're looking for the general solution so the primary solution between the domain of 0 and 2π are in degrees : 

45,90,135 and 270