Question

solve (2a-b)(2a-b), using suitable identity​

Answer 1

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• Solve $(2a - b)(2a - b)$ using suitable identity.

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$(2a - b)(2a - b)$

$= {(2a - b)}^{2}$

$= {(2a)}^{2} + {(b)}^{2} - 2 \times 2a \times b$

$= 4 {a}^{2} + {b}^{2} - 4ab$

$= 4 {a}^{2} - 4ab + {b}^{2}$

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• $(2a - b)(2a - b) = 4 {a}^{2} + {b}^{2} - 4ab$

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• ${(x - y)}^{2} = {x}^{2} + {y}^{2} - 2xy$

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• ${(x + y)}^{2} = {x}^{2} + 2xy + {y}^{2}$
• ${(x + y)}^{3} = {x}^{3} + {y}^{3} + 3xy(x + y)$
• ${x}^{2} - {y}^{2} = (x + y)(x - y)$
• ${(x - y)}^{3} = {x}^{3} - {y}^{3} - 3xy(x - y)$

Answer 2

Step-by-step explanation:

(a+b)(a-b)=a^2-b^2

$(2ab + b)(2a - b) = {2a}^{2} - {b}^{2}$