Question

Solve 2cos^2 A +6 sinAcosA +10sin ^2 A =1

Answer 1

Answer:

-18.43°

Step-by-step explanation:

$2 { \cos(a) }^{2} + 6 \sin(a ) \cos(a) + 10 { \sin(a) }^{2} = 1 \\ 1 = { \sin(a) }^{2} + { \cos(a) }^{2} \\ 2 { \cos(a) }^{2} + 6 \sin(a ) \cos(a) + 10 { \sin(a) }^{2} - { \sin(a) }^{2} + { \cos(a) }^{2} = 0$

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