Solve 2cos square x+ 3sin x=0
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Hi ,
2cos²x + 3sinx = 0
2( 1 - sin² x ) + 3sinx = 0
2 - 2sin²x + 3sinx = 0
2sin²x - 3sinx - 2 = 0
2sin²x - 4sinx + sinx - 2 = 0
2sinx( sinx - 2 ) + 1 ( sinx - 2 ) = 0
( sinx - 2 ) ( 2sinx + 1 ) = 0
Therefore ,
sinx - 2 = 0 or 2sinx + 1 = 0
sinx = 2 or sinx = -1/2
I hope this helps you.
:)
2cos²x + 3sinx = 0
2( 1 - sin² x ) + 3sinx = 0
2 - 2sin²x + 3sinx = 0
2sin²x - 3sinx - 2 = 0
2sin²x - 4sinx + sinx - 2 = 0
2sinx( sinx - 2 ) + 1 ( sinx - 2 ) = 0
( sinx - 2 ) ( 2sinx + 1 ) = 0
Therefore ,
sinx - 2 = 0 or 2sinx + 1 = 0
sinx = 2 or sinx = -1/2
I hope this helps you.
:)
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