Math, asked by priyanshugocher, 1 year ago

solve:2cos²x + 3sinx=0

avelinteresa: is the question correct

Answers

Answered by Anonymous286

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Anonymous286: at the end there is a mistake in the value of x

Anonymous286: x=7π/6 and x=11π/6

Answered by nitthesh7

= 2 cos²x + 3 sinx

= 2 (1-sin²x) + 3 sinx

(because cos²x = 1 - sin²x)

Then,

= 2 - 2 sin²x + 3 sinx

= -2 sin²x + 3 sinx + 2

Divide by (-) on whole,

= 2 sin²x - 3 sinx - 2

Let sin²x = p

= 2p² - 3p - 2

= 2p² - 4p + p - 2

= 2p(p-2) +1(p-2)

=(2p+1)(p-2)

Then, p = -1/2 or 2

Hence sinx = -1/2 and 2
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nitthesh7: if u find it as most helpful pls mark it as brainliest

Anonymous286: but sinx cannot be equal to 2

nitthesh7: S my friend as sin values lie between -1 and 1

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