solve 2cosec+2cos+{5sec_3cosec}/6sin+8cot
if measurements of a rightangled triangle is 7cm,6cm,8cm respectively
chaurasiashikhar:
it is 5sec - 3cosec ???
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Answered by
1
if its : 2 cosec+2cos+(5sec-3cosec)/6sin+8cot
then: from triangle v get :
2cosec=2* 8/6
2cos=2*7/8
5sec=5*8/7
3cosec=3*8/6
6sin=6*6/8
8cot=8*7/6
now v get: 8/6*2+2*7/8+(5*8/7-3*8/6)/6*6/8 +8*7/6
8/3+7/4+40/7-4/9/2+28/3
= 8/3+7/4+26/56+28/3
=448+294+78+1568/168
=829.3
then: from triangle v get :
2cosec=2* 8/6
2cos=2*7/8
5sec=5*8/7
3cosec=3*8/6
6sin=6*6/8
8cot=8*7/6
now v get: 8/6*2+2*7/8+(5*8/7-3*8/6)/6*6/8 +8*7/6
8/3+7/4+40/7-4/9/2+28/3
= 8/3+7/4+26/56+28/3
=448+294+78+1568/168
=829.3
Answered by
1
if its : 2 cosec+2cos+(5sec-3cosec)/6sin+8cot
then: from triangle v get :
2cosec=2* 8/6
2cos=2*7/8
5sec=5*8/7
3cosec=3*8/6
6sin=6*6/8
8cot=8*7/6
now v get: 8/6*2+2*7/8+(5*8/7-3*8/6)/6*6/8 +8*7/6
8/3+7/4+40/7-4/9/2+28/3
= 8/3+7/4+26/56+28/3
=448+294+78+1568/168
=829.3
then: from triangle v get :
2cosec=2* 8/6
2cos=2*7/8
5sec=5*8/7
3cosec=3*8/6
6sin=6*6/8
8cot=8*7/6
now v get: 8/6*2+2*7/8+(5*8/7-3*8/6)/6*6/8 +8*7/6
8/3+7/4+40/7-4/9/2+28/3
= 8/3+7/4+26/56+28/3
=448+294+78+1568/168
=829.3
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