Math, asked by shilpashroff555, 12 days ago

Solve : 2m^2 + 7m + 6

Answers

Answered by arivumathis2000
0

Step-by-step explanation:

  • 2m^2+7m+6=0
  • 2m^2+4m+3m+6=0
  • 2m(m+2)+3(m+2)=0
  • (m+2)(2m+3)=0
  • m+2=0,2m+3=0
  • m=-2,2m=-3
  • m=-2,m=-3/2
  • m=-2,-3/2

pls mark my ans as brainiest

Answered by Anonymous
0

Answer :

How to solve your question

2m^{2}  + 7m + 6

Grouping

1. Use the sum-product pattern

2m^{2} + 7m + 6

2m^{2} + 4m + 3m + 6

2. Common factor from the two pairs

2m^{2} + 4m + 3m + 6 \\ 2m(m + 2) + 3(m + 2)

3. Rewrite in factored form

2m(m + 2) + 3(m + 2) \\ (2m + 3)(m + 2)

Solution:

(2m + 3)(m + 2)

Step-by-step explanation:

@darksoul

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