Question

Solve : (2n-1)(3n+2) - (n-5) =​

Answer 1

༒࿐៚ Answer ༒࿐៚

$(2n - 1)(3n + 2) - (n - 5) \\ \\ 6 {n}^{2} + 4n - 3n - 2 - n + 5 \\ \\ 6 {n}^{2} + 0 + 3 \\ \\ 6 {n}^{2} + 3$

Answer 2

Answer:

(2n-1)(3n+2) - (n-5) =0

2n (3n+2) -1 (3n+2) -n+5=0

6n²+4n -3n -2 -n+5=0

6n²+0+3=0

6n²+3=0