Math, asked by pulkitkapoor822, 1 year ago

Solve 2nd And 3rd Sum

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Answers

Answered by sohom81
1
2nd answer
20CUBE÷5ROOT 5
=( 20SQUARE×4)÷ROOT5


3RD ANSWER
9+2ROOT15


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Answered by WilsonChong
0

Answer:

2. 20\cdot \sqrt[3]{\frac{1}{125}}=20\cdot \left(\frac{\sqrt[3]{1}}{\sqrt[3]{125}}\right)=20\left(\frac{1}{5}\right)=4

3. \left(\sqrt{5}+\sqrt{3}\right)^2=\left(\sqrt{5}\right)^2+2\left(\sqrt{5\cdot 3}\right)+\left(\sqrt{3}\right)^2=5+2\sqrt{15}+3=2\sqrt{15}+8

Hope this helps :)

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WilsonChong: Think you might need to ignore 3
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