Question

Solve 2nd And 3rd Sum

Answer 1

2nd answer
20CUBE÷5ROOT 5
=( 20SQUARE×4)÷ROOT5


3RD ANSWER
9+2ROOT15


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Answer 2

Answer:

2. $20\cdot \sqrt[3]{\frac{1}{125}}=20\cdot \left(\frac{\sqrt[3]{1}}{\sqrt[3]{125}}\right)=20\left(\frac{1}{5}\right)=4$

3. \left(\sqrt{5}+\sqrt{3}\right)^2=\left(\sqrt{5}\right)^2+2\left(\sqrt{5\cdot 3}\right)+\left(\sqrt{3}\right)^2=5+2\sqrt{15}+3=2\sqrt{15}+8

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Step-by-step explanation: