Question

solve 2nd question...
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Answer 1

Step-by-step explanation:

If x/a = y/b = z/c = k (say)

(ii) x³/a³ + y³/b³ + z³/c³ = 3xyz/abc

• Solving LHS: x³/a³ + y³/b³ + z³/c³

= (x/a)³ + (y/b)³ + (z/c)³

= (k)³ + (k)³ + (k)³

= k³ + k³ + k³

= 3k³

= 3(x³/a³) = 3(y³/z³) = 3(z³/c³)

• Now solve RHS: 3xyz/abc

= 3*(x/a)*(y/b)*(z/c)

= 3*(k)*(k)*(k)

= 3k³

= 3(x³/a³) = 3(y³/z³) = 3(z³/c³)

So, LHS = RHS

Hence, Proved✔️

Thanks! ✨