Question

solve 2powerx+1=3power1-x

Answer 1

(x+1)log2(2)=(1−x)log2(3)(x+1)log2⁡(2)=(1−x)log2⁡(3)

x+1=log2(3)−x.log2(3)x+1=log2⁡(3)−x.log2⁡(3)

x(1+log2(3))=log2(3)−1x(1+log2⁡(3))=log2(3)−1

x=log2(3)−11+log2(3)



plz mark as brainlist