solve 2x+1/10 - x+2/6 = 3-2x/15
Answers
Answer:
How to solve your question
Your question is
2
+
1
1
0
−
+
2
6
=
3
−
1
⋅
2
1
5
2x+\frac{1}{10}-x+\frac{2}{6}=3-1 \cdot \frac{2x}{15}
2x+101−x+62=3−1⋅152x
Solve
1
Divide the numbers
2
+
1
1
0
−
+
2
6
=
3
−
1
⋅
2
1
5
2x+\frac{1}{10}-x+{\color{#c92786}{\frac{2}{6}}}=3-1 \cdot \frac{2x}{15}
2x+101−x+62=3−1⋅152x
2
+
1
1
0
−
+
1
3
=
3
−
1
⋅
2
1
5
2x+\frac{1}{10}-x+{\color{#c92786}{\frac{1}{3}}}=3-1 \cdot \frac{2x}{15}
2x+101−x+31=3−1⋅152x
2
Add the numbers
2
+
1
1
0
−
+
1
3
=
3
−
1
⋅
2
1
5
2x+{\color{#c92786}{\frac{1}{10}}}-x+{\color{#c92786}{\frac{1}{3}}}=3-1 \cdot \frac{2x}{15}
2x+101−x+31=3−1⋅152x
2
+
1
3
3
0
−
=
3
−
1
⋅
2
1
5
2x+{\color{#c92786}{\frac{13}{30}}}-x=3-1 \cdot \frac{2x}{15}
2x+3013−x=3−1⋅152x
3
Combine like terms
2
+
1
3
3
0
−
=
3
−
1
⋅
2
1
5
{\color{#c92786}{2x}}+\frac{13}{30}{\color{#c92786}{-x}}=3-1 \cdot \frac{2x}{15}
2x+3013−x=3−1⋅152x
1
+
1
3
3
0
=
3
−
1
⋅
2
1
5
{\color{#c92786}{1x}}+\frac{13}{30}=3-1 \cdot \frac{2x}{15}
1x+3013=3−1⋅152x
4
Multiply by 1
1
+
1
3
3
0
=
3
−
1
⋅
2
1
5
1x+\frac{13}{30}=3-1 \cdot \frac{2x}{15}
1x+3013=3−1⋅152x
+
1
3
3
0
=
3
−
1
⋅
2
1
5
x+\frac{13}{30}=3-1 \cdot \frac{2x}{15}
x+3013=3−1⋅152x
5
Combine multiplied terms into a single fraction
+
1
3
3
0
=
3
−
1
⋅
2
1
5
x+\frac{13}{30}=3-1 \cdot \frac{2x}{15}
x+3013=3−1⋅152x
+
1
3
3
0
=
3
+
−
1
⋅
2
1
5
x+\frac{13}{30}=3+\frac{-1 \cdot 2x}{15}
x+3013=3+15−1⋅2x
6
Multiply the numbers
+
1
3
3
0
=
3
+
−
1
⋅
2
1
5
x+\frac{13}{30}=3+\frac{{\color{#c92786}{-1}} \cdot {\color{#c92786}{2}}x}{15}
x+3013=3+15−1⋅2x
+
1
3
3
0
=
3
+
−
2
1
5
x+\frac{13}{30}=3+\frac{{\color{#c92786}{-2}}x}{15}
x+3013=3+15−2x
7
Subtract
1
3
3
0
\frac{13}{30}
3013
from both sides of the equation
+
1
3
3
0
=
3
+
−
2
1
5
x+\frac{13}{30}=3+\frac{-2x}{15}
x+3013=3+15−2x
+
1
3
3
0
−
1
3
3
0
=
3
+
−
2
1
5
−
1
3
3
0
x+\frac{13}{30}{\color{#c92786}{-\frac{13}{30}}}=3+\frac{-2x}{15}{\color{#c92786}{-\frac{13}{30}}}
x+3013−3013=3+15−2x−3013
8
Simplify
Subtract the numbers
Subtract the numbers
=
7
7
3
0
+
−
2
1
5
x=\frac{77}{30}+\frac{-2x}{15}
x=3077+15−2x
9
Multiply all terms by the same value to eliminate fraction denominators
=
7
7
3
0
+
−
2
1
5
x=\frac{77}{30}+\frac{-2x}{15}
x=3077+15−2x
1
5
=
1
5
(
7
7
3
0
+
−
2
1
5
)
15x=15(\frac{77}{30}+\frac{-2x}{15})
15x=15(3077+15−2x)
10
Simplify
Distribute
Cancel multiplied terms that are in the denominator
Rearrange terms
1
5
=
−
2
+
7
7
2
15x=-2x+\frac{77}{2}
15x=−2x+277
11
Add
2
2x
2x
to both sides of the equation
1
5
=
−
2
+
7
7
2
15x=-2x+\frac{77}{2}
15x=−2x+277
1
5
+
2
=
−
2
+
7
7
2
+
2
15x+{\color{#c92786}{2x}}=-2x+\frac{77}{2}+{\color{#c92786}{2x}}
15x+2x=−2x+277+2x
12
Simplify
Combine like terms
Combine like terms
1
7
=
7
7
2
17x=\frac{77}{2}
17x=277
13
Divide both sides of the equation by the same term
1
7
=
7
7
2
17x=\frac{77}{2}
17x=277
1
7
1
7
=
7
7
2
1
7
\frac{17x}{{\color{#c92786}{17}}}=\frac{\frac{77}{2}}{{\color{#c92786}{17}}}
1717x=17277
14
Simplify
Cancel terms that are in both the numerator and denominator
Divide the numbers
=
7
7
3
4
x=\frac{77}{34}
x=3477
Solution
=
7
7
3
4
Answer:
here is your answer
Step-by-step explanation:
take LCM 2x+1/10 - and LCM of x+ 2/6 = LCM OF 3- 2x/15
after solving it cross multiply it and and the value of x will be 3.19 approx...
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